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NCERT Class 7 Maths Textbook Chapter 11 With Answer PDF Free Download

Chapter 11: Perimeter and Area
Here are some of the concepts in this chapter.
- Squares and Rectangles
- Triangles as Parts of Rectangles
- Generalising for Other Congruent Parts of Rectangles
- Area of a Parallelogram
- Area of Triangle
- Circumference of a Circle
- Area of Circle
- Conversion of Units
- Applications
11.1 INTRODUCTION
In Class VI, you have already learned the perimeters of plane figures and areas of squares and rectangles.
Perimeter is the distance around a closed figure while the area is the part of plane or region occupied by the closed figure. In this class, you will learn about perimeters and areas of a few more plane figures.
11.2 SQUARES AND RECTANGLES
Ayush and Deeksha made pictures. Ayush made his picture on a rectangular sheet of length 60 cm and breadth 20 cm while Deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. Both these pictures have to be separately framed and laminated.
Who has to pay more for framing, if the cost of framing is 3.00 per cm? If the cost of lamination is 2.00 per cm2
, who has to pay more for lamination?
For finding the cost of framing, we need to find the perimeter and then multiply it by the rate for framing. For finding the cost of lamination, we need to find the area and then multiply it by the rate for lamination.
Author | NCERT |
Language | English |
No. of Pages | 24 |
PDF Size | 2.2 MB |
Category | Mathematics |
Source/ Credits | ncert.nic.in |
NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area
Q2. Find the area of a square park whose perimeter is 320 m.
Q3. Find the breadth of a rectangular plot of land, if its area is 440 m2 and the length is 22 m. Also, find its perimeter.
Q4. The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area.
Ex 11.1 Class 7 Maths Question 1.
The length and the breadth of a rectangular piece of land are 500 m and 300 m respectively. Find
(i) its area
(ii) the cost of the land, if 1 m2 of the land costs ₹ 10,000
Solution:
Given: l = 500 m, b = 300 m
(i) Area = l × b
= 500 m × 300 m = 150000 m2
(ii) Cost of land = ₹ 10,000 × 150000 = ₹ 15,00,000,000
Ex 11.1 Class 7 Maths Question 2.
Find the area of a square park whose perimeter is 320 m.
Solution:
Given: Perimeter = 320 m
Side of the square = Perimeter 4
=3204m=80m
Area of the square = Side × Side
= 80 m × 80 m = 6400 m2
3. Find the breadth of a rectangular plot of land, if its area is 440 m2 and the length is 22 m. Also find its perimeter.
Solution:-
From the question it is given that,
Area of the rectangular plot = 440 m2
Length of the rectangular plot = 22 m
We know that,
Area of the rectangle = Length × Breadth
440 = 22 × Breadth
Breadth = 440/22
Breadth = 20 m
Then,
Perimeter of the rectangle = 2(Length + Breadth)
= 2 (22 + 20)
= 2(42)
= 84 m
∴Perimeter of the rectangular plot is 84 m.
NCERT Class 7 Maths Textbook Chapter 11 With Answer PDF Free Download