Exponents And Powers Chapter 13 Class 7 Maths NCERT PDF

NCERT Solutions for Class 7 Maths Chapter 13′ PDF Quick download link is given at the bottom of this article. You can see the PDF demo, size of the PDF, page numbers, and direct download Free PDF of ‘Ncert Class 7 Maths Chapter 13 Exercise Solution’ using the download button.

NCERT Class 7 Maths Textbook Chapter 13 With Answer PDF Free Download

Chapter 13: Exponents And Powers

13.1 INTRODUCTION

Do you know what the mass of earth is? It is
5,970,000,000,000,000,000,000,000 kg!
Can you read this number?
Mass of Uranus is 86,800,000,000,000,000,000,000,000 kg.
Which has greater mass, Earth or Uranus?
Distance between Sun and Saturn is 1,433,500,000,000 m and distance between Saturn
and Uranus is 1,439,000,000,000 m.

Can you read these numbers? Which distance is less?
These very large numbers are difficult to read, understand and compare.

To make these numbers easy to read, understand and compare, we use exponents. In this chapter, we shall learn about exponents and also learn how to use them.

AuthorNCERT
Language English
No. of Pages16
PDF Size1166 KB
CategoryMathematics
Source/ Creditsncert.nic.in

NCERT ML Aggarwal Solutions Class 7 Maths Chapter 13 Practical Geometry

Q3. Express each of the following numbers using the exponential notation:
(i) 512 (ii) 343 (iii) 729 (iv) 3125

Q5. Express each of the following as a product of powers of their prime factors:
(i) 648 (ii) 405 (iii) 540 (iv) 3,600

1. Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. If this line meets l at S, then what shape do the two sets of parallel lines inclose?

Solution:

Steps of Construction:

(i) Draw a line l and P be a point not on the line l

(ii) Take a point A on line l and join PA

(iii) Draw a line m which is parallel to line l on point P

(iv) Take a point Q on line l and join PQ

(v) From a point R on line m, draw a line parallel to PQ which meets l at point S

Here,

We can observe that PQRS is a parallelogram

3. Construct a triangle PQR given that PQ = 5.4 cm, QR = PR = 4.7 cm. Name the triangle.

Solution:

Steps of Construction:

1. Draw a line segment PQ of length 5.4 cm

2. Taking P and Q as centers and radius 4.7 cm, draw two arcs intersecting each other at point R

3. Join PR and QR

Here, the two sides are equal of length 4.7 cm

Hence, the required △RPQ is an isosceles triangle

NCERT Class 7 Maths Textbook Chapter 13 With Answer PDF Free Download

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